y(y^2+1)dx+x(y^2-1)dy=0

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Solution for y(y^2+1)dx+x(y^2-1)dy=0 equation: 


Simplifying
y(y2 + 1) * dx + x(y2 + -1) * dy = 0

Reorder the terms:
y(1 + y2) * dx + x(y2 + -1) * dy = 0

Reorder the terms for easier multiplication:
y * dx(1 + y2) + x(y2 + -1) * dy = 0

Multiply y * dx
dxy(1 + y2) + x(y2 + -1) * dy = 0
(1 * dxy + y2 * dxy) + x(y2 + -1) * dy = 0
(1dxy + dxy3) + x(y2 + -1) * dy = 0

Reorder the terms:
1dxy + dxy3 + x(-1 + y2) * dy = 0

Reorder the terms for easier multiplication:
1dxy + dxy3 + x * dy(-1 + y2) = 0

Multiply x * dy
1dxy + dxy3 + dxy(-1 + y2) = 0
1dxy + dxy3 + (-1 * dxy + y2 * dxy) = 0
1dxy + dxy3 + (-1dxy + dxy3) = 0

Reorder the terms:
1dxy + -1dxy + dxy3 + dxy3 = 0

Combine like terms: 1dxy + -1dxy = 0
0 + dxy3 + dxy3 = 0
dxy3 + dxy3 = 0

Combine like terms: dxy3 + dxy3 = 2dxy3
2dxy3 = 0

Solving
2dxy3 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '2'.
dxy3 = 0

Simplifying
dxy3 = 0

The solution to this equation could not be determined.

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